2.5x^2=42x

Solution for 2.5x^2=42x equation:

2.5x^2=42x

We move all terms to the left:

2.5x^2-(42x)=0

a = 2.5; b = -42; c = 0;
Δ = b2-4ac
Δ = -422-4·2.5·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-42}{2*2.5}=\frac{0}{5}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+42}{2*2.5}=\frac{84}{5}
=16+4/5
$